# Squaring a Shed

• posted on August 10, 2003, 8:00 pm
How does one go about making sure a shed is square? Is there a formula like 3' down one side, 2' down the oposite side should produce 5' across? Help.
Thanks in advance.
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 10, 2003, 8:09 pm
Measure one leg over 3'. Measure the other leg up 4'. The hypotenuse will be 5'.
Use the same edge of the tape on both marks when you go to check the 5'.
You can also double/triple/quadruple this (6', 8', 10') for a larger building and to check that your wall isn't "running out".
UA100
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 11, 2003, 5:58 pm

Also: 5 ft high, 12 ft wide, *should* give 13 ft on the hypotenuse.
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 10, 2003, 8:26 pm
Measure diagnaly.

Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 10, 2003, 9:57 pm

And who says that public schools aren't doing their job? Apparently, it's not just a problem in the US.
If you want a right angle, if you create a triangle with sides of 3 units, 4 units, and 5 units, the angle between the 3 and 4 unit sides is a right angle.
If you have a floor or wall laid out and want to check it for square, make sure the diagonals are equilateral (oops...I mean the same length).
todd
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 10, 2003, 11:55 pm
How about a(squared) + b(squared) = c(squared) where 'a' and 'b' are the sides next to the (hopefully) 90 deg corner, and 'c' is the hypotenuse (diagonal). It works regardless of the length of either short side.

Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 11, 2003, 12:27 am
wrote:

A Pythy response.
The old boy would be proud.
Regards, Tom Tom Watson - Woodworker Gulph Mills, Pennsylvania http://users.snip.net/~tjwatson
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 11, 2003, 10:22 pm
John DeBoo wrote:

If opposite walls are the same length, your method will get the walls parallel and thus right angles. It doesn't work if one of an opposite pair is shorter, i.e. you don't have a rectangle. You use geometry for squaring a base. I'm curious about your "square the walls with the floor tho." Nobody does that. You want the floor level and you want the walls to be perpendicular. To do that you use gravity. To get something level you use water (absent flow and wind, water surfaces are always level)(most people use a tube since any surfaces connected will be level) and to get walls perpendicular you use a plumb bob. Those methods are basic and the standard. Of course most people just use a level which is a derivative method, i.e., the level has to be adjusted to something else to be sure the bubbles indicate level and perpendicular.
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 12, 2003, 6:25 pm
Thanks for all the replies, some good ideals here.

Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 12, 2003, 9:47 pm
You were close. 3, 4, and 5.
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 13, 2003, 1:05 am
In rec.woodworking snipped-for-privacy@aol.com (ToolMiser) wrote:

Yep, good ol' Pythagorous. Of course, if it is squarely dimensioned, simply measure diagonal corners across and adjust till the measurements are equal.
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• posted on August 13, 2003, 8:29 pm
ToolMiser wrote:

or 5,12,13 or 7,24,25
ARM
Add pictures here
<% if( /^image/.test(type) ){ %>
<% } %>
<%-name%>
• Share To

HomeOwnersHub.com is a website for homeowners and building and maintenance pros. It is not affiliated with any of the manufacturers or service providers discussed here. All logos and trade names are the property of their respective owners.