fair enough, but i really dont think that the young lady on the phone
with me at b&d was thinking along those lines.
well, i'd rather have a battery that i know will never nuke my motor,
given that ive already been burned once. literally.
you are saying use the dewalt battery pack, and be aware of the
limitations. this would be like driving a car which would suffer
engine damage if you went over 55mph. doable, but nerve wracking.
No, I am saying regardless of what battery pack you use if you push the
drill beyond its limits it will eventually fail. A weaker battery pack will
still burn the motor up if the motor is under a constant strain. Having a
stronger battery pack may supply the power to ease the strain.
well, i guess i still have to play it conservative. i dont have any
way of quantifying whether or not i should expect theoretical damage
to the drill, and my practical experience seems to match up with the
doomsayer version of the dewalt-firestorm debate.
thanks for your help, though.
When you turn on the tool the voltage across the battery drops, you
can demonstrate this with a voltmeter on your car pretty easily. in
fact in some cars with voltmeters on the dash you can see it from the
drivers seat. The voltage drop will be less with a higher rated battery,
so more current will flow through the circuit. The key to
understanding this is that batteries have resistance too.
If we are talking using a higher voltage battery in a tool designed for a
lower voltage battery, then, yeah, you can do some damage...especially in
extended runs. However, putting any 18v battery as the energy source for
ANY 18v drill is NOT going to hurt the drill at all. 18v is 18 v and it
matters zip where it comes from. What the differences in the batteries do
determine is how long the drill will run in normal use and (if the drill
motor has to work against a too high load)how easilly it will stall
because you have drained the battery against a stalling load.
Now if you stall the drill then you can damage it using a larger capacity
18v battery simply because the better battery will not go dead as quickly
as the weaker one will and you will be running current through a stalled
motor longer, over-heating it and damaging it. The weaker (less current
capacity) 18v battery will be delivering near 0v while the better battery
will still be supplying 18 v.
Don't abuse the drill, and it will thrive with either battery...it will
just do it longer w/o recharging with the better battery.
Lawrence Wasserman wrote:
- nopcbs (none of the time)
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