TIA Ron

--

Ron Hock

HOCK TOOLS -- http://www.hocktools.com

Ron Hock

HOCK TOOLS -- http://www.hocktools.com

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the

I believe this is what you're looking for (bottom) http://www.delorie.com/wood/chord-radius.html

Man, this web thing takes the joy out of trying to remember old
HS geometry!

Anyways, came up with the same thing, R = (x^2 + y^2)/(2*y), where y is half the length of the chord and x is the height above the chord...

i.

Norm Abrams wrote:

Anyways, came up with the same thing, R = (x^2 + y^2)/(2*y), where y is half the length of the chord and x is the height above the chord...

i.

Norm Abrams wrote:

above

Thanks everyone. You saved me a lot of research time and I never even
thought of using AutoCad...

Ron

Ron

--

Ron Hock

HOCK TOOLS -- http://www.hocktools.com

Ron Hock

HOCK TOOLS -- http://www.hocktools.com

Click to see the full signature.

http://mathforum.org/library/drmath/view/55037.html

link to XL spreadsheet (watch out for line wrap)

http://216.239.51.104/search?q Êche:6GIlO2OZGFMJ:www.ukuleles.com/spreadsheets/ArcCalcs.XLS+chord+radius+length+arc&hl=en&ie=UTF-8

link to XL spreadsheet (watch out for line wrap)

http://216.239.51.104/search?q Êche:6GIlO2OZGFMJ:www.ukuleles.com/spreadsheets/ArcCalcs.XLS+chord+radius+length+arc&hl=en&ie=UTF-8

--

Ken Vaughn

Visit My Workshop: http://home.earthlink.net/~kvaughn65 /

Ken Vaughn

Visit My Workshop: http://home.earthlink.net/~kvaughn65 /

Click to see the full signature.

wrote:

Let l be the length of the chord h be the chord-arc height

r the radius and d the distance from the centre to the chord

Then r = ( (l^2* / 4) + h^2 ) / *2h

d = ( (l^2* / 4) - h^2 ) / *2h

Let l be the length of the chord h be the chord-arc height

r the radius and d the distance from the centre to the chord

Then r = ( (l^2

d = ( (l^2

That's easy. AutoCAD.

UA100

UA100

Yes, the $3400 calculator. You can do better for a lot less money.

He would cut a ten foot radius I would assume.

He would cut a ten foot radius I would assume.

[top-posting fixed]

I was more thinking along the lines of how, but Bruce's suggestion is a good one.

todd

I had to cut a twenty four foot radius for a template one time. I did it
with a router circle jig.

good

good

In rec.woodworking

You could make a string compass and draw that part of the arc on a sheet of cardboard. Go out on the driveway if you need room. Done.

You could make a string compass and draw that part of the arc on a sheet of cardboard. Go out on the driveway if you need room. Done.

The optimized formula is: chord squared, divided by 8 times the height, then add half the height.

example: chord: 10 height: 2

radius = ((10*10)/(8*2)) + 2/2 radius = (100 / 16) + 1 radius = 6.25 + 1 radius = 7.25

The derivation of the above gets messy.

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