No the idiot CD doesn't understand that if the drain really is a few nano amps as stated by the op then a 10Mohm meter will drain it at least a hundred times faster than the device will.
CD is incapable of working out what resistance will produce the stated standby current at 5V and it isn't as low as 10Mohms.
So his inability to understand anything makes him try to drag anyone that does down to the same level of idiot that he is.
But what do you expect from a troll.
You sure? I thought the OP said that it draws 5µA at 5V. I make that
1Mohm.
An 1822 battery fits a Makita power tool, so it should last a bit in a laptoop.
But the OP said microamps.
Just checked and I must have miss read it. But never mind its only a "bit" out.
I don't think Makita are using the convention for sizing cylindrical cells/batteries which is being referred to. Mind you, I have never seen a CMOS battery that big eiither.
it's a microamp, not a micro amp.
Why? He wanted to know how long the capacitor would be able to keep the memory active. It's much easier if viewed as a simple (dis)charge problem.
Didn't you ever calculate the ripple voltage on a reservoir capacitor to make sure that any downstream regulators would not drop out under load? I certainly did. It's much easier if you consider it from a rate of change of charge viewpoint.
Thanks, it was nothing really. I find that Ctrl-C --> Ctrl-V is much quicker than using the drop-down menus.
Impostor!
They didn't have microamps way back in Dennis's day; they'd only just discovered milliamps. ;-)
how would he cope with nanoamps
In article snipped-for-privacy@candehope.me.uk>, charles snipped-for-privacy@candehope.me.uk> scribeth thus
Do we have Femtoamps
Seen them 10-15 as watts used in RF systems..
Try yoctoamps!
Be a bit of a bugger measuring them eh?..
You probably have to count the electrons.
More like count the days between electrons
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