I have a giant sequoia, approx. 17 in tall (43 cm). That is from the
ground up, not including the roots. Currently it is in a pot. My
question is, how big should the pot be?
Thank you for any help,
Your looking at a tree that gets aweful BIG, I'm talking up to 100ft, pot? Rose
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I have one which is now about 20 inches tall. It was about 12 inches tall
when I bought it 2 years ago. So in my climate at least, it grows slowly.
Mine is in the ground - but it was in an 8 inch pot when I bought it.
From the site posted earlier:
In the best plantations, giant sequoia averaged 0.5 to 0.7 m (1.6 to 2.3
ft) per year in height growth, and 1.3 to 2.0 cm (0.5 to 0.8 in) in
diameter growth per year (9).
Rooting Habit- During the first few years, the root system of giant sequoia
seedlings consists of a taproot with few laterals-a habit that facilitates
survival during dry summers (36). The ratio of root length to shoot height
during this period is about 2 to 2.5, with drier sites having higher ratios
(17). After 6 to 8 years, lateral root growth predominates, and elongation
of the taproot practically stops (36).
You give the height to be about 43 cm, so if you go by the above, the tree
is about a year old and the proper depth for the current pot should be
around say 100 cm or 40". Calculations for 2 additional years of growth
are left as an exercise for the reader.
In other words, start shopping for pots, learn bonsai, or tranplant the
sapling to a non-potbound location.
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