One last try...
Start with a square 34" on each side. Choose one corner and measure along
the side 16" and make a mark. From the same corner measure 16" along the
other side and mark it. Connect the two marks forming a 'diagonal' line. Its
length is 22 5/8". This should satisfy all the conditions set down by the
OP. Does this solve her problem?
It isn't the diagonal of 31.11" which is the governing number, it's the TV.
To enclose it we need a trapezoid with 25" (front of TV) and 19" (rear of
TV) parallel sides with a height of at least 19" (length of TV). In
addition, the overall container can have one side 34" long maximum (door
jamb). Again start with a 34" square. Proceed as in my last post, except
change the 16" dimension to 17 3/4". When completed, the box has a 25" wide
face for the TV screen, two rear adjacent 34" sides and will contain a TV
with a 25" wide face, 19" wide rear and about 26" long.
But she wasn't trying to design the cabinet anymore by then. She already
had the shape she liked. She was wondering how the TV was able to fit in
the scale mock-up when the front dimension of the cabinet seemed smaller
than the TV.
HomeOwnersHub.com is a website for homeowners and building and maintenance pros. It is not affiliated with any of the manufacturers or service providers discussed here.
All logos and trade names are the property of their respective owners.