BS 1362 fuse standard

May 29, 2014 3 Replies

I was trying to work out the time/current factor for BS 1362 plug top fuses for a fault current. Figure 2 is the logarithmic graph. They've managed to plot the curves on log base 11 axes (labeled in base 10)!



It makes a difference of 100A in the answer, depending how you read the broken graphs!


I'll risk ridicule: is it just that they have used minor grid lines at

1.5, 15 etc? I suggest that becauSe of the way the 2nd interval in each major grid is smaller than both the 1st and 3rd intervals. And because if I draw a log-log graph in Excel using base 10 it looks like figure 2 but for the fact it don't have the (spurious? misleading?) minor grid line.

I'll go to the stocks ready to receive punsihment ;(

I think you might be right - the extra line could be 1.5

Every alternate line is labeled, and the labels run:

10^n 2 4 6 8 10^(n+1)

So the line between 10^n and 2 could be 1.5. It sure can't be 1!

If so, the axis lines are:

10^n 1.5 2 3 4 5 6 7 8 9 10^(n+1)

Thanks - I can now read the value off the graph.

You mean this one:

formatting link

I think they have just added extra "half" lines on the first two divisions since they are quite large in comparison to the rest in each decade.

Join the Discussion

Have something to add? Share your thoughts — no account required.

Didn't find your answer?

Ask the community — no account required