The engines are NOT the same on the snow blowers. Some have Briggs and
Stratton, some are Tecumseh and others are Honda powered. Finding the size
that I need in measurements that I am not familiar with is the problem.
Buying a size that is not up to what I require will inevitably result in the
machine being inadequate for the job at hand.
On Sat, 10 Oct 2009 09:35:04 -0400, "Worn Out Retread"
Foot lbs X rpm /5252 is horsepower. So you need to know the RPM.
The reason they have done this is because several companies were sued
for over-rating the horsepower their engines actually put out.
Like a lawn mower has a 4.5 HP engine (rated at 3600 rpm by the
manufacturer) but because of the blade length and safety regulations
the engine is limited to 2400 RPM on the mower (maximum velocity of
discharge limit). So the 4.5HP engine is now 2.85 HP - but it is STILL
a 6.56 ft lb engine.
It is all matter of useful HP and useful torque. HP rating is often very
misleading. If Peak HP occurs near top rpm it won't be good. I'd pay
more attention to torque. I still remember what I was told when I was a
kid. Torque is how big a stump an engine can pull, HP is how fast.
That is the point of the question asked. I want to buy a machine of at least
the same power as the old machine but the system of measurement has changed
so that creates a problem that I have to solve before parting with my money.
On Sun, 11 Oct 2009 11:00:05 -0400, "Worn Out Retread"
You have the tools now.
The old engine was rated at 3600 RPM - universally. So your new engine
torque X 3600 /5252 is the rating of old engine that is equivalent.
If it is an OHV engine it will usually have a broader power range, so
will do MORE work than the old side valve equivalent, and on less
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