Please help solve this 12V electrical circuit puzzle

Jan 07, 2010 23 Replies

I knew the ballpark. I knew it had to be close to 33 and 4 but I didn't know the exact number and I needed an answer accurate to the 3rd decimal place.

It's for a scavenger hunt and the answers are clues to the next item on the list.

=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D= =3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D=3D= =3D=3D=3D=3D=3D=3D Hey: An idea? Maybe the 'Yellow' items illuminate (i.e. Are lamps or LEDs)? And maybe the 'Red' items are resistors. Does that throw a different light on the question? Sorry for the bad pun!

In rference to 12 volts and 35 ohhms. V over R =3D Amps So 12/35 =3D 0.34 amps. And Volts times Amps =3D Watts So 12 x 0.34 =3D 4.1 watts. Or you can do it another way; Amps squared times R. So (0.34 x 0.34) times 35 =3D 4.1 watts.! Check! Or another way again; Voltage squred divided by R. So (12 x12) divided by 35 =3D 144/35 =3D4.1 watts. Check!

If I am thinking correctly, the answer is readily apparant with 2 seconds of thinking and almost no calculations. "Distance" from one conder to the opposite is 3 resistors = 3 ohoms. But there are 4 different paths which are all equal by symmetry -- so like 4

3-ohm paths in paralle or 3/4 ohms total.

Took me 100 times as long to write it out as to solve it...

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