Electrical Outlet Wiring

Oct 19, 2007 47 Replies

True, true.

But if you have insulated tools the only times you mgith actually have contact is when you are doing "preliminary" wire twisting or are handling things like switches our outlets.

You can strip and bend and twist wires without touching them directly.

At one particular time, you would see different voltages (and could figure out the current would be different). You could not see phase without seeing more than a singe instant.

There's many cases where honesty is NOT the best action. I often get into trouble for that reason.

And try to never touch more than one at a time. Of course perfection doesn't exist and there's no way you can guarantee no mistakes.

BTW, I once touched a hot (120VAC) wire while replacing a switch, and felt nothing at all.

is u r google broken u sad pathetic loser social reject

By "instantaneous current", I really meant "instantaneous current as a function of time". If you look at the phase currents with an oscilloscope, you can see that there is a phase shift between phases, so the current waveforms are not equal. The question was asking about average current as a scalar, not vector, quantity.

Or more generally, providing the "full" answer to a question when the asker only wanted the quick one-sentence executive summary. Most people just want an answer, they don't want to understand the reason behind the answer. I'm one of the people who always wants to know where the answer came from, and how approximate the answer is, but I seem to be in a distinct minority.

Dave

And a "scaler" is a "vector" with some information ignored. In that situation, I did not know just what information was supposed to be ignored.

One that's wrong.

That seems to be true. This mental laziness contributes to a lot of problems. Things are much easier to understand when you know what's going on.

And there's nothing wrong with that, as in the quote on my homepage '"I was almost normal once, but then I got better.". Simplistic, but generally true.

Today I found he time to complete this task. The unswitched light and the switched socket were on two different circuits. I identified and turned of these circuits. Once I removed both the light and socket from their mounts, the wiring in both cases was very simple. All I did was switch the light and socket with their mounts and all is well. Thanks for all the input. Somehow I expected the switched outlet wiring to be much more complicated, but instead the whole circuit is switched.

re "Now that you've told the world what you did here with a post that may be findable 'forever' I suggest you check the code and if needed change the installation to be code compliant..."

Or at least re-post and *tell* us that you changed it. ;-)

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