Changed one light bulb - now both light bulbs dont work

Yep, idiot me....should be wattage.

No, there's no "higher load" issue. Halogen incandescent bulbs are just like standard incandescent bulbs electrically. Both types have a high inrush current until the filament heats up and becomes a high-resistance load. But that heating only takes milliseconds. Switches, dimmers and other controls are "tungsten rated" to handle the inrush current. Normal house wiring doesn't care since it happens so quickly.

Tomsic

Where's the ballast in my ceiling fan?

Does you ceiling fan require more voltage to start than to run? I didn't think so.

Depends on the use of the word "require."

I'm pretty sure a ceiling fan starts on less voltage than it runs on, because I think the inrush current is enough to drop the supply voltage momentarily.

However, I imagine if you gave it a little extra voltage (capacitor bank, etc.) so that the starting voltage could NOT drop, it would still start fine.

Look at the lights in a ceiling fan and see if they dim or not when the fan is started. I bet not.

I will give it to you that there is a voltage drop before the motor spins up, but it is so small that it will not be noticed. About like putting one more brick on a truck load of bricks. It is there, but the engine will not notice it.

The motor runs on AC and the capacitors would not be able to store any enegery to help the motor every time. It would depend on where in the cycle you start the motor, and if started in the wrong part, would actually reduce the voltage if used like you want them to. Again the reduction would be so slight it would go un noticed.

No, it really doesn't.

Nonsense.

No, the capacitor is used to create a phase shift to get the fan turning (in the desired direction), NOT to increase voltage, which it doesn't.

, etc.) so that the starting voltage could NOT drop, it would still start f ine.

Yeah, I know what a start capacitor does and what a run capacitor does.

And that's not what I'm talking about. I'm talking about having sufficient voltage supply so as not to have a voltage drop during that tiny period wh ere inrush current makes the voltage sag. I thought of a capacitor in the circuit out of a hazy and imperfect recollection of Maxwell's laws, and the use in power supplies, but it's probably not the best solution.

Regardless, when an AC motor starts, before it starts turning it draws a la rge current, and drawing a large current normally makes voltage sag.