On Mon, 11 Apr 2016 11:06:36 -0500, Gordon Shumway
Well I did pay attention in class and found geometry to be fun and
made a good grade.
I tried to solve this by using a^2 = (B^2)+(C^2) to find the long
leg. The answer didn't seem right so I am looking to check it.
From the calculator above I made a mistake. Some where.
Thanks for the calculator.
One thing I noted about geometry was that guys good at the pool table
weren't necessarily good at geometry.
5/12 is a particularly convenient slope actually. It's one of the famous
Pythagorean Triples. Sides of 5, 12 and 13 make a right triangle. So if
your horizontal and vertical measurements were actually 12 and 5, the
"hypotenuse" length would be 13. If it's something else, just multiply
the horizontal measurement by 13/12.
Your equation should work. Use the numbers above as an example 13^2
(169) = 5^2 (25) + 12^2 (144)
I wonder if you added up the squares of the two legs but forgot to take
the square root of the result.
Happens to all of us. I used to be familiar with Calculus, but after
college never calculated a derivative other than to show off. Now I'm
filling the space with more important things... Like how to properly hit
a softball. Let me tell you it's not about swinging your arms. Your
entire body is involved.
On 11 Apr 2016 20:04:27 GMT, Puckdropper
always said that we'd probably never use the skills again after
graduation but that I should know how to use integration tables.
Unfortunately, they never taught how to use them. I never really
needed them, either but at times it would have been good to know.
On Monday, April 11, 2016 at 4:33:53 PM UTC-4, krw wrote:
I think it's less about using the skills you learned in high school and more about
The ability to learn what you need know to accomplish what you are trying to do
Is more important than any given subject matter.
On Mon, 11 Apr 2016 18:54:54 -0700 (PDT), DerbyDad03
Sorry, that should have been "four semesters".
I don't agree. Secondary school should be about learning things that
you will need to become a productive citizen. That includes learning
how to learn but it also includes at least "business" math, some
history and civics. Unfortunately it's now more about indoctrination.
I didn't have any "calculus" in high school, though. We were taught
all of the foundations for it but not the grind. ;-)
The foundations are pretty important. Without arithmetic (and I'll
include at least beginning algebra) you're toast in any technical
field (everything is now). Without learning some sense of history and
civics, we're doomed (they don't and we are - hopefully I won't see it
but I'm not so sure).
Since I posted I pictures last year, I didn't mention it this year, but
I made my 2nd pilgrimage to Colonial Williamsburg a few weeks ago. The
antique furniture in the museum is starting to feel like old friends and
I spent enjoyable time in the cabinetmakers shop. Recommended, if you're
on the eastern side of the country. This time, my wife brought plenty of
apples for some of the horses (the ones that weren't currently working).
But back to history, after my visit above, I became more curious about
the related history prior to the mid 18th century. Wikipedia contained
the following reference which I found interesting (Note: I didn't finish
In a nutshell, it describes some of the dynamics between the new
"settlers" and the indigenous (Indian) population. Wikipedia, of
course, contains a lot of historical facts in bite-size pieces. I owe
credit Williamsburg for fostering my interest (making me a slightly
more-informed individual). I still have a lot of catching up to do, I
suppose. ; )
On Monday, April 11, 2016 at 11:27:20 AM UTC-5, swalker wrote:
Shooting pool ain't just about geometry. Left spin, right spin, back spin,
over the top spin, force of the shot, hard kiss, soft kiss, it all adds up
to making the ball go everywhere but in the pocket. Doubt old Pythagoras
ever shot a game of pool in his life.
Don't forget that Pythagorus requires a right triangle.
Take the triangle formed by the roof (22.5/22.5/135 degrees),
bisect into two right-triangles, then use trig to calculate
the hypotenuse length, since you know the length of the
adjacent side (1/2 the length of the long side of the
original triangle - the long side is opposite the 135 degree
cos(90) = adjacent/hypotenuse
hypotenuse = cos(90)/adjacent
area = 2 x (hypotenuse x length of roof).
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