Hi, I would like to make a round waste basket that is 12" round at the top and 8" at the bottom. I will be using 2"x1/4" hardwood slats. Is there some simple formula that I can use to figure out how wide the bottom part of the slats will be tapered, the angle to cut the edge and how many slats will be needed? Many Thanks, John
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John wrote:

If you approximate it as a circle, then
Circ = pi* Dia
Using 2" slats, this gives 12*pi/2.85 slats.
So plan on 19 slats.
You could use the circle approximation and be pretty close, but we may as well get exact.
If you draw a triangle from the centre of a 19-sided polygon to the centre of an edge and the outer point of an edge, the central angle will be 360/(2*19) or 9.47 degrees. Remember this for later, as it's also the bevel you'll need for the sides of the slats.
Trig says that
sin(theta) = opposite/hypotenuse
so
sin(theta) = s/2r
where
theta = central angle s = length of the side r = distance from outer vertex to centre
plugging in a slat width of 2", we get a max diameter of 12.15" which is pretty close to what you asked for.
For the bottom, if we start with a desired max diameter of 8", this gives a slat width of 1.317".
As mentioned above, you'll want to bevel the edges at 9.47 degrees from vertical.
Chris
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Thank you, looks like I need to go back to school and learn math all over again, LOL Thanks Again, John
On Tue, 29 Nov 2005 23:24:06 -0600, Chris Friesen

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John wrote:

Hi John, Pi times 12 = 37.699. Pi times 8 = 25.133. Divide 37.699 by the actual width of the slats to find how many slats you'll need. The bottom of the slat will be 0.666 times the width of the top of the slat. Without knowing the height of the basket, I can't give you the angle. -Mike
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Thank you Mike, the height would be 12". Regards, John
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