Dividing A Circle Into Thirds

Nov 28, 2003 23 Replies

It is -provably- *PRECISELY**CORRECT*.

strike a circle, radius OA ('O' is the center, 'A' is on the circle) strike an arc, of the same radius, centered at 'A', intersecting the circle at 'B'

_by_definition_, 0A, and 0B are the same length, each being a radius of the circle. AB was constructed as the same length as OA.

THEREFORE, 0AB is an *equilateral*triangle*. and all the angles are *precisely* 60 degrees.

Repeating the process around the circle will lead to _exactly_ *six* such equilateral triangles, which *precisely* fill the entire 360 degrees of the circle.

Don't feel bad. I was going to complain as well, but I looked up the formula for the chord of a circle first :-).

Draw a circle with a compass. Set the compass on the edge of the circle and draw an arc to cross the circle. Reset the compass at one of the intersections and repeat. You'll get 6 equal sections of the circle. Easy.

Andy Dingley provided one (good) method of finding the center of a circle...

Here's a method I often use, which is a tad simpler:

Place the point of a compass (or dividers) on the original circle A somewhere, and make a new circle B. If you can, make circle B just a little bigger than A, but the size really isn't important.

Draw two more circles, C and D, the same size as B. Place C's center on one of the intersections of A & B. Place D's on the other. Note that C and D both will intersect A at B's center.

Now draw a line through the two intersections of B and C, and another line through the two intersections of B and D. The two lines intersect at the center of A.

This is much easier to do than to describe. Only takes a few seconds. When you see how the elements fall together, you will realize that you don't need whole circles. Short arcs in the appropriate places suffice.

Jim

Join the Discussion

Have something to add? Share your thoughts — no account required.

Didn't find your answer?

Ask the community — no account required