If an error of nearly 1mm is ok for your purposes, 10/10. ;-)
[OT] Simple arithmetic
Jan 26, 2017
60 Replies
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I got 9 on my iphone and 9 using google.
That's the point : it should be 2.071067818 ;-)
A simple non-mathematical solution could be to say that the circle and square are both symmetrical about both diagonals - so it has to be the centre of the circle.
Its implicit in the proposition that he drew a square as small as possible ROUND the circle and exactly in the same place AS the circle.
By symmetry, both must have their centres co-incident.
Well doing it in my head gives 1. Windows Calculator (Scientific mode) gives 9 (so does my TI scientific calculator), but you have to insert a x between the 2 and the (, as it doesn't understand that a value next to a ( means that you have to multiply the value with the result of the contents of the brackets, and this takes priority over the division.
- There's a missing operator
- BODMAS
In (written) algebra, a value before a left bracket means multiply the result of the contents of the brackets (first).
Really? How about default to multiplication - is that no longer the rule?
so 6÷2 *3 = 1
(Unless something incorrectly gives you 9 of course)
In message , "Dave Plowman (News)" writes
Well, a tad over two feet was close enough :-)
Do iPhones know that? I don't have one.
PS I assumed you meant key into the phone *exactly* what you posted.
Like this you mean
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both 1 and 9 are correct depending.....
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... on whether you're a f****it or not.
...on operator precedence.
Just like punctuation, if you don't have rules that everybody sticks to, language is ambiguous
No, it depends on what 6/2*3 is held to be.
And whether you consider there is an implicit bracketing of 2(1+2)
You mean in like "Let's eat grandma?"
Exactly.
Or Eats, Shoots, and Leaves.
I was taught BODMAS (brackets, orders (powers), division, multiplication, addition, subtraction) as the order in which to apply operators.
So:
- evaluate 1+2 first because it's in brackets.
- there are no orders/powers
- evaluate 6 / 2 = 3
- evaluate 6 (ie 6/2) * 3 (ie 1+2)
- there is no addition or subtraction (other that 1+2 which was evaluated early because it's in brackets).
Therefore the answer is 9.
On the other hand, should the 2(1+2) be evaluated before the division because a gut feeling says that an implied multiplication should have a higher-than-normal precedence - and it *is* only gut feeling: I couldn't explain why!
I'd have written the expression with a few more brackets to make it abundantly clear what I meant: so either
6 / (2(1+2)or
(6/2)(1+2) aka (6/2)*(1+2)
Exactly.
Relying on operator precedence when it's very shaded is a bad idea.
AS is relying on implicit type conversion in a boolean operation, as I also know to my cost.
Javascript type casting is defined for assignment, but not for comparison.
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