(I also posted this in uk.tech.digital-tv but the loving sentiment is the same)
Hello all,
Please forgive what must seem like a pointlessly trivial question to many of you, but I am not overly confident with mathematics (and I trust this group!) and would like to learn about...
Arctan!
I have a mobile phone with a particular camera on it which claims to have a field of view of 188 degrees, and a focal length of
1.66 mm. I would like to calculate the sensor width from these figures.
Field of view = 2 x arctan (sensor width / (2 x focal length))
so
118 = 2 x arctan (S.W. / 3.32)
then by the magic of magic I presume:
59 = arctan (S.W. / 3.32)
But then what? If the brackets weren't involved I'd have a better idea, but they are, so I don't.
And what about the arctan operator when juggling things about? Is it like square root and square?
If anyone can help me with this I would be very grateful. It is only curiosity, nothing more urgent than that. (Nokia 7.2 wide angle lense, if anyone is wondering.)
Thank you in advance,
David Paste.