Got some numbers/calculations to support that? Is that including the next door neighbors with their PV installation?
daestrom
-------------------
Sure! Basic Ohms lawa and a wire resistance table
The chart shows we would use 2/0 copper (assuming solid copper, but it won't be)
In a 100 feet of overhead run to a house, down the stack and through the meter to the main panel, where the fuses or breakers are, not considering the impedance of the overcurrent devices (that allegedly cannot handle a fault this big) we come up a with a minimum copper resistance of
200 feet (has to return) x 0.07793 x 10^-3 Ohms / foot (oh look ...your old units too) = 0.015586 OhmsUsing 240 Vac as the fault supply (it won't be under a faulted condition) the max fault current would be
240 Vac / 0.015586 Ohms = 15.4 kA.Now we haven?t figured in any of the other impedances (very generous) and any approved O/C device in a panel these days is rated at 100kA. The old "code" fuses were 10kA and no amount of lowering the impedance of the grid source using a PV generator attempting make it lower than 0 Ohms impedance is going to increase that fault current. In real life this fault current would be below 5kA after connection impedances, transformer winding impedance, primary impedance, ferrous openings, smaller conductors used by the utility that uses free air rating on smaller conductors, etc.. etc...
Engineering people do not worry about fault currents at residential services unless special circumstances apply, like within a few feet of a commercial busbar splitter without enough wire in between. Then they know how to close their eyes and say "Nobody told me."
Mike