What is the best way to repair a hole in the wall that was punched in
by a door handle?
My first thought is to use those steel mesh things that you just
adhere over the area, mud, sand and texture.
Recently I also learned that you can cut out a square/rectangle and
install a piece of replacement sheetrock held by "instabacks" - those
brackets that allow you to anchor sheetrock adjacent to sheetrock. Or
use a couple pieces of wood behind the wall might work for this
purpose also. The problem would then be I have to mud and tape 4
sides which I'm not the best at. I have tried this in the garage and
looks decent but I'm not sure if I am up for it for inside the house.
Or maybe this technique might be better for bigger holes.
So I am thinking that with my skills.. the mesh patches might blend in
better rather than being able to see a subtle rectangular repair.
What's is your opinion?
If the holes aren't too large you might consider covering them with some
doorknob wall bumper plates. Some of them have rubber pads on them. They
will avoid future damage unless someone REALLY whacks the doorknob into
the wall. Or, at least put a bumper on after you patch the wall.
Like on this page:
Cut it out enough to get a couple of scab boards behind the hole. Secure
them in place. Add the drywall patch. Finish two sides at a time. Getting
in a hurry and trying to do all 4 at the same time results in frustration
and an inferior job for most of us.
So whole cares if it takes a week to do it right as long as it looks great
when you are done?
I pick up some paint mixing sticks(free at HD) to use as back supports for
wallboard patches;glue or screw them in,and the same for the patch.They cut
easily,score them with a utility knife and snap off what you need.
My method for fixing such holes is as follows:
1) If the punch out is in one piece, save it.
2) Make a support board to place behind the hole. I usually rip a 2x4 about
1/2" thick and 5 or 6 inches long.
3) Put a temporary drywall screw in the middle of your board to hold it
tight against the inside of your hole, while you put a couple of screws in
your board to hold it in place. Remove your temporary screw.
4) Screw your saved piece (punch out) to the support board you installed.
You can make a replacement with a hole saw, if your punch out is broken up
or lost inside the wall. A rectangular patch works too of course, depending
on your hole.
5) Mud/tape and sand as required. Makes a nice patch.
I also use this for repairing any holes I made to fish wires.
1. Cut off the loose wall board
2. Using construction adhesive in a caulking tube, glue thin wood such as a
piece of yard stick to the back of the wall board (inside the wall)
3. Glue a piece of wall board on to wood support.
4. Patch with wall board compound (follow instructions on package.)
Home Depot's profits.They chose to accept slightly(very slightly) lower
profits in order to give them away.The sticks price is probably so low,it's
not worth the time to inventory,price them,and ring them up.
And it's not like people are going to go into a collecting frenzy.
People pick some up when they buy paint or other HD products.
One additional method just for grins. I don't see any single method being
intrinsically superior to another:
1-Cut a square/rectangular hole be sure to make it large enough to get all
damaged drywall. When you make the cuts, bevel the edges at about
30-45degrees making the outer edges wider than the inner edge.
2-Cut the patch with beveled edges to fit. The beveled edges will ensure
that the patch will not fall through the hole.
3-Butter the edges of the patch with drywall mud and insert it in the hole.
4-Tape, mud, sand the patch as required.
Just my two cents worth.
Phila has an average daily min and max of 67.2 and 86.1 F in July. Two A ft^2
vents with one-way plastic film dampers and a 16 ft height difference and a
DT (F) temp diff would allow 16.6Asqrt(16DT) cfm to flow at night, cooling
a house by cfmDT Btu/h. What would the average July temp be in a house with
10K Btu/F of thermal capacitance and 200 Btu/h-F of conductance and no internal
heat gain and 2 4'x4' vents with a 16' height difference, and no fan?
20 THv'initial house temp (F)
30 FOR D=1 TO 100'simulate 100 average July days
40 FOR H=0 TO 23 STEP .1
50 TA=(86.1+67.2)/2+(86.1-67.2)/2*SIN(2*PI*H/24)'outdoor temp (F)
60 IC=(TH-TA)*200'conductive loss (+) or gain (-)
70 IF TH>TA THEN IV.6*16*SQR(16)*(TH-TA)^1.5 ELSE IV=0'vent cooling (Btu)
80 TH=TH-(IC+IV)/10000*.1'new house temp (F)
90 NEXT H
100 NEXT D
110 PRINT TH
75.96505 (close to the average daily temp) with no vent
69.50536 (2.3 F above the min) with 2 4'x4' vents
With a higher house conductance, the vents make less difference, eg 73.3
vs 69.5 F at 1000 Btu/h-F. The vents above would move a 24-hour average
16.6x16sqrt(16(76.7-69.5)) = 2851 cfm, comparable to a whole-house fan.
With humidity sensing and motorized dampers, they could help heat a house.
I don't dispute any of the calculations. I have, however, lived in Philly
in the summer. While the average max may be 86.1 degrees, that is the
temperature taken at the weather station. In the city, it can easily be 90+
for days on end and lows in the high 80's as the heat sink of a brick row
house and concrete sidewalks holds the energy.
Northing beat an air conditioner for comfort.
I, too, have lived in Philly. Come July you won't feel like doing those
In the days of the British Empire, Philly was considered a "hardship post",
due to the extreme summer heat. I have had friends from New Dehli, one of
the hottest places on the planet, say that West Philly, where they resided,
was just as bad.
I think we can ignore humidity if ventilation is only used for cooling,
vs heating in shoulder seasons. Can the outdoor dewpoint Tod be greater
than the indoor wall temp Tw, if the outdoor dry bulb temp To is less than
the indoor dry bulb Ti and Ti is close to Tw? Tdo = To/(1-TolnRo/9621),
using a Clausius-Clapeyron approximation, with Tdo, To, and Ti in Rankine
degrees and the outdoor RH Ro expressed as a fraction.
To/(1-TolnRo/9621) > Ti makes
To > Ti - TiTolnRo/9621, or equivalently,
9621(To-Ti) > - TiTolnRo.
This can't happen, since the left side is negative, since To < Ti,
and the right side is positive, since 0 < Ro < 1.
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