On Tuesday, May 31, 2016 at 6:36:49 PM UTC-4, FromTheRafters wrote:
OMG, more stupidity.
"The natural number one with an exponent of two can equal two under the
An exponent of two is a number raised to the second power. It's the
number times itself. Now explain to us how 1 x 1 = 2.
On Mon, 30 May 2016 16:50:22 -0400, FromTheRafters
Lost power in the circuit is a function of the voltage drop.
It is all moot in the case of the resistance heater in the example
that started this nonsense thread.
All of the power lost to voltage drop will still be returned to the
home in the form of heat and that was the object of the exercise in
the first place.
Yes, it sure does. I always heard of that as power *loss* or copper
*loss* though. Power Drop was a sort of tap which went from the pole to
The term 'voltage drop' was only used in circuits with current flowing
through them. All of the deflections aside, I'm still not ready to
believe that a blown fuse has a voltage drop across it no matter what
these brainiacs say.
On Mon, 30 May 2016 20:40:56 -0400, FromTheRafters
It HAS tyo have, because with zero(or as close to zero as the real
world can produce) current flow in the conductors and an ipressed
voltage of 120, or whatever volts across the cirduit, the voltage HAS
to drop across something - in this case the "infinite" or "undrfined"
resistance across the blown fuse.
email@example.com has brought this to us :
It's not a 'voltage drop' when there is no current. Voltage drop exists
because of the dissipation of energy across the device under
There's not much simple about physics.
"Zero electrical DC resistance
The simplest method to measure the electrical resistance of a sample of
some material is to place it in an electrical circuit in series with a
current source I and measure the resulting voltage V across the sample.
The resistance of the sample is given by Ohm's law as R = V / I. If the
voltage is zero, this means that the resistance is zero."
If there was no voltage (a voltage drop actually) measured, you would
be fooled into believing that there is zero resistance if you leave out
the part about the need to have current flowing through the device.
With no current, you can't trust Ohm's Law to give a meaningful result.
See above where R = V / I. If I is zero, R is *undefined* not "zero" or
The above example uses a "circuit" (not an open circuit which isn't
actually a circuit at all) and a "current source" with current flowing
through the device.
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