We are installing a new whirlpool bath in an older home, upstairs. The
joists are probably fir (ca. 1900), a real 2x11, 16" oc, spanning 15
feet. Being conservative, I give the tub, loaded with people and water,
1700 lbs / 16.5 sq feet. (103 lbs / sq. ft) Location is adjacent to
outside bearing wall, which is 16" granite.
Will we end up in the kitchen below? How might we reinforce the floor to
I have a two story garage, the second floor garages two heavy vehicles
(Mercedes MLs) and is supported on 2x10s on 16" centers spanning 9 feet
between steel beams. Your true 2x11 members have a little over 2x the
load carrying capacity of a 2x10 (1.5x9.5). Even though your span is
longer I don't think you'll have any problem if the members are in good
E. Paul Wileyto wrote:
It is a common misconception that cars represent a significant load
in a structure.
My little car weighs 2200lb and is about 13x6 feet or about 78 sq. ft.
While it is approximately four point loads of 550lb, the average load
is only 2200/78 = 28.2 psf. This is far less than the 103 psf that the
water-filled tub represents.
If we assume a 6000lb vehicle that's 15x7, then the average load is
6000/105 = 57 psf. Don't forget that one foot of water depth
represents a 64 psf load.
Best advise - if you're worried, contact an engineer; if you're not
worried, make sure your insurance is paid up.
HomeOwnersHub.com is a website for homeowners and building and maintenance pros. It is not affiliated with any of the manufacturers or service providers discussed here.
All logos and trade names are the property of their respective owners.