# gallons of fuel oil vs depth in tank

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• posted on December 10, 2007, 10:37 pm
Desiglass wrote:

I remember this being an example problem in high school calculus.
http://www.arachnoid.com/calculus/volume2.html
I think you'll be better off getting a chart from your fuel oil supplier.
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• posted on December 11, 2007, 12:44 am
wrote:

Easy. Measure the depth of oil in inches. Multiply by 11.458 to get the number of gallons.
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• posted on December 11, 2007, 1:02 am
Phisherman wrote:

That constant would only be valid for a straight sided tank. Since the tank is a cylinder there will be different areas and thus different volumes at each sample point.
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• posted on December 11, 2007, 2:37 am
Yeah you could do the math. Simple way: draw a circle on a piece of graph paper. Count the squares inside the circle and ratio to your numbers. Assume this should be close enough for your application.

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• posted on December 11, 2007, 3:56 am
You didn't do very much googling. This is the #1 result.
http://www.greertank.com/tankcalc.htm

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• posted on December 11, 2007, 4:21 am
On Mon, 10 Dec 2007 21:56:36 -0600, "S. Barker"

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• posted on December 11, 2007, 10:56 am
wrote:

http://www.greertank.com/tankcalc.htm
Sure it does. After you put in the tank dimensions, you actually have to click to get the proper chart for that tank. Is your mouse broken?
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• posted on December 11, 2007, 4:51 pm
well the hell it doesn't. You enter your tank size, then hit the dipstick button and it give a chart. Done deal. All he wanted to know is how much oil at a certain inch level.
s

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• posted on December 11, 2007, 4:28 am
This one does.
http://www.1728.com/cyltank.htm
On Mon, 10 Dec 2007 21:56:36 -0600, "S. Barker"

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• posted on December 11, 2007, 5:23 am
I like S. Barker's link. It will make a dipstick chart that can be printed.
Terry wrote:

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<%-name%>
• posted on December 11, 2007, 4:53 pm
Thank you Bill. I was beginning to think i was seeing things.
s

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• posted on December 11, 2007, 5:11 pm

Also, for those who want to know what the tanks look like, on Greer Tanks homepage,
http://www.greertank.com /
There is a (not really very good) picture of a stack of them, probably at their fabrication yard in Fairbanks, Alaska.
They also have a location in Washington state, so perhaps the name is known in the Pacific Northwest too, but in Alaska there name "Greer Tank" is seen *everywhere*.
--
Floyd L. Davidson <http://www.apaflo.com/floyd_davidson
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• posted on December 11, 2007, 4:52 pm
Are you on crack or what?
s

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• posted on December 11, 2007, 4:20 am

If, as you say, it is a cylinder that is 4 feet across and 6 foot deep, the formula goes something like this:
Volume in c.f. = 3.14*2^2*6 cfu.36 76.36 c.f. = 563 gallons.
Reversing the equation: 550 gallons = 73.52 c.f. So your 550 gallons is at 5.85 feet, say 5'10", which makes sense because you want to avoid a spill.
Knowing that, a cylinder is linear, so:
550 gallons / 70" = 7.86 gallons per inch.
So, at 16" there 125.76 gallons.
If however, the tank isn't really cylindrical, then you're pretty well screwed because the math gets a lot harder. It would take a bit to figure the formula, but you could assume the tank to different shape and you could easily approximate it, say be dividing it into 10 horizontal slices and calculating the volume of each slice.
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• posted on December 11, 2007, 4:47 am
wrote:

Some online calculators [most also create charts] ------------------------------------------------- <http://www.greertank.com/tankcalc.htm <http://www.odayequipment.com/TankChart/Tankchart.asp <http://www.wemactanks.com/tankcalc.htm <http://www.1728.com/cyltank.htm
For the (idealized) mathematics of a horizontal cylindrical tank (flat ends) see, for example:
<http://mathworld.wolfram.com/CylindricalSegment.html esp. (26) [picture toward bottom of page]
and the related page <http://mathworld.wolfram.com/CircularSegment.html esp. (18)
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<%-name%>
• posted on December 11, 2007, 4:47 am
wrote:

Here is the whole chart.
start: CLS 'INPUT "h="; h FOR n = 1 TO 47 h = n h = h / 12 hh = h r = 2 IF h > r THEN h = r * 2 - h pi = 3.1415926536# d = r - h c = 2 * SQR(h * (2 * r - h)) height = 6 totalvol = pi * (r ^ 2) * height * 7.48051945# a = (2 / 3) * c * h + (h ^ 3 / (2 * c))
v = a * 6 * 7.48051945# IF hh > r THEN v = totalvol - v
PRINT n, v
NEXT n
inches gallons 1 2.860469 2 8.037283 3 14.66704 4 22.42931 5 31.1326 6 40.64345 7 50.86079 8 61.70386 9 73.10578 10 85.00963 11 97.36603 12 110.1314 13 123.2671 14 136.7381 15 150.5129 16 164.563 17 178.8624 18 193.3876 19 208.1174 20 223.0329 21 238.1176 22 253.3575 23 268.7409 24 284.2597 25 295.2769 26 310.6605 27 325.9003 28 340.985 29 355.9005 30 370.6303 31 385.1555 32 399.4549 33 413.5049 34 427.2798 35 440.7508 36 453.8864 37 466.6519 38 479.0082 39 490.9121 40 502.314 41 513.1571 42 523.3745 43 532.8853 44 541.5886 45 549.3508 46 555.9806 47 561.1574
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• posted on December 12, 2007, 2:43 am
You need to find a twelve year old girl, and ask her. Someone with math skills.
--

Christopher A. Young;
.
.

"Desiglass" < snipped-for-privacy@stny.rr.com> wrote in message