Ok, one acre is 43560 square feet so , if a perfect square, one
dimension should be half that? So the lot should be 21780 deep. So that
should be about 2/10ths of a mile deep?
How deep is a 113 acre lot that is a perfect square?
That's wrong. If one square acre is 208.7 on side, that's half of a 10th
of a mile since one tenth is 528 feet. So 113 acres should be 23,583.1
on a side or 44 tenths? that 4 miles, I don't think so. Is it?
I've no clue how you're trying to do arithmetic but it ain't comin' close.
Couple of ways...
Sq rt(43560 * 113) = 2218.6... ft
2640 (1/2-mi) * sq rt(113/160) = 2218.6... ft
2218.6/2640 ~0.84 so is, as noted early, short of the half-mile.
First from area (ft-sq)/A; second from previous ratio of sq-rts of
acreage compared to known side distance.
Fundamentally, A = L x W if L = W then A = L^2 --> L = sqrt(A)
area is measure by length times width, which is where you're mistaken
a perfectly square acre is 208.71 feet in length on all four sides.
113 acres perfectally square would be 2,218.62 feet on all sides.
This is about 2/5 of a mile on each side.
A perfect square a mile long on all four sides equals 640 acres.
Which is what I told you before if compare to a quarter-section... :)
(or :(, not sure which...)
And, of course, 1A = 1 rod by 1/2-mile is the way we laid out fields
years ago....Now, simply punch in coordinates on the GPS system in the
tractor cab and stop when says "done". :)
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