I apologize for this being way off topic, but there appears to be some smart folks
here and I thought I would ask a few questions.
If a regular pendulum clock, which keeps quite accurate time, were taken from the
Earth to the Moon and the correct time set into the clock and the clock was
restarted, would the clock keep as accurate time as it did on Earth?
Would the clock's three weights have to be pulled up every 7 days as mine does?
Would the lower Lunar gravity make any difference in time keeping?
If so, which way and by how much?
If not, why not?
p.s. The Sun will rise in the East regardless of the above.
Looks like your question is how gravity affects a pendulum. A pendulum's
movement is caused by gravity. Since a pendulum is just another falling
object it should fall with the same acceleration as a free falling object
(neglecting friction). An object on Earth will fall at 32 ft/sec^2. An
object on the moon will fall with (I think) with 1/6 that acceleration, and
1/6 as fast. (An object in space, without gravity, will not fall at all).
So a pendulum on the moon will keep time more slowly than on Earth. It
seems like it should be 1/6 as fast, but I don't know exactly how the clock
works, so maybe 1/6 isn't right.
dwhite <--- at least that's how it looks to me
Just a little searching would get you this:
Period goes as 1/sqrt g, so the clock would run slow by 1/sqrt 6. I'm not
sure of the six...look up lunar gravity. The clock would need different
If the clock is running more slowly, then the weights must be falling more
Here are clock pages:
Obviously one can make a gravimeter (device to measure the strength of
gravity) using a pendulum, given the equation.
Use your google.
Pendulum swing time= 2 * pi * sqrt (l) / g
So the clock time will slow down in direct proportion to reduced
gravity. A pendulum about 1/36 (or so) of the length would set it
right though, as the time is also proportional to the square root of
It'll also stop working pretty quickly. The moon's atmosphere is a
hard vacuum, and a dusty vacuum at that. Vacuum system lubrication is
_difficult_ (many satellites lost because of it). Even low vapour
pressure oils boil away in the vacuum and you're left with a sticky
goo that jams mechanisms. Run the bearing clean and dry and you may
get metallic welding instead. Then if you do find a bearing that
works, the lunar dust is reputedly a real hazard for any long-term
mechanism. With no air or moisture, there's not much to lay the dust
and fine dust gets everywhere (Apollo suits started to show damage in
just a few days)
They'd descend at exactly the same rate (in clock hand-movement terms)
as on Earth. They may also need to be made heavier, as their mass
would stay the same but they'd only have 1/6th of the weight - is this
still enough to drive the clock ?
Doh ! My memory must be going - that should of course be
2 * pi * sqrt (l / g)
(which considering the dimensions would have told me anyway)
So you'll run slow at about 1/2.5, or a 1/6 pendulum rod would fix it.
Jeweled bearings, sealed case. It should run *more* accurately in a
vacuum. Remove air and you remove a whole set of variables.
24 hours unwinds the same amount of cord.
How complex is the mechanism? Does it drive three hands, or one?
Or is it just a pendulum, which can by itself be considered a clock. You can
read time simply by counting the beats. Hands add nothing more than
Father Haskell, you raise several interesting points. I understand the dry bearing
problem in vacuum since I worked for Dr. von Braun for about 20 years before he was
forced to leave Huntsville.
With the lower gravity on the Moon, dust would settle in the near area, but more
than on Earth, and not be blown about at all since there is no Lunar atmosphere of any
significance. There are no winds on the Moon. [well, the Solar Wind, but that is
another topic entirely] AFAIK, moisture has nothing to do with time keeping per se.
"24 hours unwinds the same amount of cord."
I assume you mean on the Moon as well as on the Earth. On the Moon, I now think the
clock would unwind 1/6 of the cable per a real 24 hours. so we seem not to agree on
IMHO, you have missed the point. I would agree with you IF the clock kept the same
on the Moon as on Earth, but I now do not think that it would and other reply posters
seem to say that as well. I believe that it would take about 6 x 7 days for the clock
to run down, assuming that it now runs down in 7 days here on Earth - or in that neck
of the woods. In other words, the pendulum would move more slowly and there would be
fewer pendulum cycles, or ticks, per real minute on the Moon. Ergo, the clock would be
inaccurate and run slower and the hour and minute hands would correspondingly also
I think it matters not how complex the mechanism is or how many hands the clock has.
The atmosphere and moisture are not factors because I had assumed the clock would
remain inside a manned Lunar Lander of some kind. I did not state that assumption and
that is my error. So forget about atmosphere and moisture - or lack thereof outside of
the Lander. The clock would not be exposed to the Lunar environment - other than the
My Howard-Miller GF clock has 2 hands and 3 weights actually.
I thank you for your interesting reply.
"'Vonce ze rockets go up, who cares vere zey come down,
dat's not my department,' says Werner Von Braun." (Lehrer)
The tower shot of the Apollo 11 liftoff still leaves me speechless, regardless. My
favorite arg to the moon hoaxers is, well, where did this monster end up?
Related point -- check out record producer George Martin's autobiography. Seargent
Pepper was cut with a pendulum-regulated turntable. Martin knew this was something
special, and wanted every detail done perfectly.
Oh yes - and now there is a DVD of it. The ending was different from Poe's novel IIRC.
Vincent Price starred in it.
Here is one URL for the DVD:
Minor quibble having little or no effect on the discussion.
Although Moon gravity is appx. 1/6 Earth gravity, the Earth's atmosphere causes dust
to remain in suspension and settle quite
slowly. No atmosphere means dust on the Moon literally drops like a rock. So, in
actual effect, dust on the Moon falls much more
rapidly than on the Earth.
Wichita, KS USA
Quite correct Tom. IIRC, there was one Apollo flight where an astronaut, on video,
dropped a feather and a more massive and compact
object at the same time. Both the feather and the other object fell at the same rate
and hit the Lunar surface at the same time.
The reason for that, of course, is that there is no atmosphere on the Moon. I think
we fully agree on this. You just stated it
differently than I did and quite well I think. TKX
The weighs do not fall continually, they fall a fixed amount at each "tick"
as the paws engage and disengage.
Most likely two of the weights drive the pendulum and one the chimes.
The pendulum is driven at the end of swing going both directions. In
many clocks this is redundant and as long as one or the other weight
is would it will run just fine.
Having messed up the night before and not getting this message sent to
the news group as I intended, I'm reposting now (slightly modified).
Umm, no on the "tides" influence.
The moon does not spin in relation to the earth and thus the tidal
forces are fixed: if the seas on the moon were full of sea water
there would be no tides coming in and going out.
If the moon was covered with water it wouldn't be round, it would
bulge out on the sides facing and turned away from the earth.
In regards to the sun: it's too far away to have near the effect the earth
would have (assuming the moon spun). Also, it's the different distances
from two points on a body to the other body that creates tidal forces,
the moon is smaller so the distances are nearer the same as thus tidal
forces are smaller. A gas planet will experience greater tidal forces
than a rock the same mass in the same orbit.
It would be just as accurate, just ticking at a slower rate.
Well, I guess that depends on what you mean by "accurate": the
clock would mark time at a stable rate but the rate would be
much slower than here on earth.
Nobody ever set a fixed swing rate for pendulums.
it's all a bit fuzzy now but I seem to remember reading sometime in
the last few years an article about the moon and it's orbital
relationship with Terra. yes, one side always faces the earth, sorta.
the moon wobbles quite a bit. the "back" side does have a bit of area
that has never been visible to earth, but it's a lot smaller than you
but in relation to the sun the moon *does* spin. the effects of
gravity obey the square of the distance bit, and the sun is a long way
away, but it's also freakin' huge. nothing compared to the grav effect
of Terra, but non-trivial.
and the moon is basically a rock, though there is some recent data
indicating that it may have a squishier core than previously thought.
OK, but _who's_ homework assignment is this?
This usually shows up in about an 8th-grade science class.
The _stability_ of the time tick will be unchanged.
The _frequency_ will be lower. By a factor of about 2.42.
The weights have to be pulled up after the same number of cycles of the
pendulum. Which will take about 17 days on the moon.
The frequency of a pendulum is proportional to the square root of the
local gravitational constant.
Thus, since Lunar gravity is _less_ than that of Earth, the frequency
will be lower. And the clock will run slower.
"How much?" The factor is the square root of the ratio of the gravitational
field strengths. A quantitative answer is left as an exercise for the
student. <Big sh*t-eating grin>
Actually, it will be much less accurate.
Think tides. They would be much greater on the moon, due to the greater
gravitational attraction of the Earth. The gravitational attraction of the Sun
would have a greater effect as well - while it would be the same on the Moon as
on the Earth, it would be greater proportionally to the Moon's own weaker
Other than those "outside influences", the pendulum should be just as accurate
on the Moon as on the Earth. Slower, but just as accurate.
HomeOwnersHub.com is a website for homeowners and building and maintenance pros. It is not affiliated with any of the manufacturers or service providers discussed here.
All logos and trade names are the property of their respective owners.