My wife is doing an OU science course which involves making a zinc/copper/vinegar battery and getting it to power an LED.
Using:
- galvanised nails about 10 mm long (under the electroyte)
- copper wire from lighting grade twin-and-earth cable about 10 mm below electrolyte
- distilled white vinegar
- each cell is an ice cube in size (we're using a plastic ice cub tray)
- each cell has a zinc electrode and copper one, with them connected in series (zinc in one cell connected to copper in the next, etc)
With no load, and with 14 cells in series, we're getting about 8 V.
However even with the load of an LED, that voltage drops to 1.4 V - just too low to light an LED which needs about 1.6 V.
I've measured the resistance of the LED and it's about 300 k ohms when biassed one way and upwards of 10 M ohms the other way. I presume that the
300 k ohms bias is the correct way to light the LED.
By my reckoning, there is an ideal zero-resistance voltage source in series with the battery internal resistance and in series with the load.
So V(load) / V(ideal) = R(load) / (R(load) * R(internal)) potential divider
V(load) / ((V(ideal) * R(load)) = 1 / (R(load) + (R(internal))
substitute measured values
1.4 / (8 * 300k) = 1 / (R(internal) + 300k)
taking reciprocals
8 * 300k / 1.4 = R(internal) + 300k
1700 - 300 = R(internal)
R(internal) = 1400 k ohms
This is *very* different from the typical figures that I can see online of of about 700 ohms (not kilohms) per cell.
I'm trying to work out what could have gone wrong.
The zinc nails have become coated in a dark plating where they have been under the vinegar, and this happened even without any correct flowing.
I've added a few grains of salt per cell to improve ion mobility (a suggested way of lowering internal resistance).