Need to be chunky diodes though 1500 W @ 230 V is 6.5 A and 4 W disipation per silicon diode. To get 5 V (still AC) you'd need eight diodes and thus over 30 W of dissipation and then the back to back set of eight, 60 W...
6.25A rms, 8.8A peak, and for a motor about 3x that for startup, so 25A diodes. I tend to get things like that from dead or obsolete PC psus, no need to buy. 5/8 = 0.625v, you wont find a non-schottky power diode dropping as little as that at 8.8A. 1-1.5v each is more realistic. 0.6v is when it begins to conduct at low i.
No. First a relay only needs about half its rated coil V to operate, so about
2.5v, say 3v to be safe.2nd, 3v at 6.25A rms = 19w. You dont double it, half the time the power's dissipated in one string, half the time in the other.
FWIW the relay coil sees a square wave.
NT
To follow up; I can confirm that the Status adaptor works perfectly. It can take a full 13A (and has a built-in replaceable fuse) and works exactly as desired.
In case it matters for others considering it, the master device needs to consume at least 30W to ensure the slave is triggered on, and less than 10W to turn off again. There's no slave overrun when the master turns off.
Highly recommended for a tenner all-in. Thanks everyone for the help tracking a device like this down.
Mathew
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