Yes. The radio waves still travel at the same speed, but the bandwidth available, and hence the possible speed of data transmission, varies inversely with the signal strength.
- Vote on answer
- posted
10 years ago
OT: Aerials on substations
Loading thread data ...
- Vote on answer
- posted
10 years ago
Sorry, that should read "Varies directly with the signal strength" In other words, the stronger the signal, the faster you can transmit data, be it digital or analogue.
- Vote on answer
- posted
10 years ago
Is half a cycle a unicycle?
Bill
- Vote on answer
- posted
10 years ago
Well of course. That's why FM and DAB are always out of sync, because the FM transmitters are stronger.
Bill
- Vote on answer
- posted
10 years ago
That's what I was trying to explain.
Bill
- Vote on answer
- posted
10 years ago
:)
It's all to do with the design of the breakers. By using very high contact pressure they can keep the moving contact mass down, so that it can be moved very quickly (by soddin' big springs) indeed. The idea is to open the contact so fast that the fault current hasn't got time to reach it's full value. They *have* to open the contacts very fast otherwise, in some cases, the fault current will either weld them shut or blow them to bits. In some circuit breaker designs the magnetic field caused by the fault current is used to help push the contacts open. All clever stuff. :)
- Vote on answer
- posted
10 years ago
10 mS to repair a fault wooooo... B-)
No uni is one. Half is hemi (greek), demi (latin), or semi (french) so it would be a hemicycle or demicycle or semicycle
- Vote on answer
- posted
10 years ago
I can see how the encoding can be encrypted to defy an attack from the outside, but what is to stop wholesale jamming of these safety critical signals?
- Vote on answer
- posted
10 years ago
on 31/03/2014, Brian Gaff supposed :
You would maybe need to be on the beam of the antenna to be able to hear it at all.
- Vote on answer
- posted
10 years ago
No its due to signal prrocessing delays.
- Vote on answer
- posted
10 years ago
- Vote on answer
- posted
10 years ago
If there's a long yagi at both ends the power into the tx will be low.
Bill
- Vote on answer
- posted
10 years ago
You don't say.
Sorry, I just realised this is the DIY group. My joke would have worked better elsewhere.
Bill
- Vote on answer
- posted
10 years ago
I thought fast opening was also related to killing the arc.
- Vote on answer
- posted
10 years ago
Not most of the time. I do have attenuators to check for this sort of thing. The Icom device is well respected for lack of spurii and good overload margins.
Brian
- Vote on answer
- posted
10 years ago
Yes, I'll send in the Pigeons to get it to move and fall to bits. Brian
- Vote on answer
- posted
10 years ago
Yes, I could get a simple vcr to transmit down the garden quite well withtwo yagis. I'm sure that power is pretty minimal.
Brian
- Vote on answer
- posted
10 years ago
I wonder how small amount of a cycle you need to work out frequency. Pass the Pi. Brian
- Vote on answer
- posted
10 years ago
So what is a Nanocycle? Is there a picocycle as well? Brian
- Vote on answer
- posted
10 years ago
Pretty obvious really, as what do you do if you want to get a better signal to noise? You narrow down the bandwidth of the receiver, but that loses you the high frequencies of course.
What has always confused me is carrier based morse code. It is simple and low bandwidth, yet in theory any fast change from nothing to something should have an infinite bandwidth, ie the leading edge of a square wave, which is rich in harmonics. So although one can sometimes hear the key click outside the bandwidth if the signal os strong, generally the bandwidth is still low. Brian