My swimming pool is losing about 1/2" to 1" of water per day.
Is this normal?
Specs: 22,000 gallons 3 ft to 6 ft deep Located in Southern California
Thanks,
Wes
My swimming pool is losing about 1/2" to 1" of water per day.
Is this normal?
Specs: 22,000 gallons 3 ft to 6 ft deep Located in Southern California
Thanks,
Wes
Yes normal without a solar cover. Go out and buy one of those fish that put out the invisible solar cover. I have the one with the battery operated pump, every 1 hour it puts out a little juice that puts a film on the pool to slow down the evaporation it works great and only cost me $19 and lasts for 60 days for my size pool (14X25).
Rich
check this out
from
If the pool is not being used frequently (then obviously), it is unlikely that the problem is splash out. On the other hand, if it is the middle of the Summer, with high temperatures and lots of kids getting in and out (dripping wet) this could, in fact, be a real cause.
To eliminate evaporation or splash out pool water loss as a causes, here is a quick test that can be run on your swimming pool:
Once you figure out if you are actually losing water in the pool via a leak, and that is not just evaporating or splashing out, there are a few more tests that can done - but now might be a great time to call in a pool professional to evaluate the situation.
Sounds like a leak.
Put out a bucket of water in the shade and see if it evaporates that fast.
Look for leaks, usually they will be found around the skimmer.
Food coloring works great for this.
Hmmm...
Water must be VERY expensive where you live.....still, losing an inch per day ???--I call bullshit !!!
Yes. Mine loses at least that much. I live in Las Vegas. I would check for leaks, but evaporation can be more than one would expect.
Steve
Maybe not. One ASHRAE swimming pool formula says a square foot of pool loses 0.1(Pw-Pa) pounds per hour or water, ie 0.46(Pw-Pa) inches per day, where Pw and Pa are the vapor pressures near the water and in the air around the water, in inches of mercury column.
Pa = 29.921/(0.62198/w) = RHe^(17.863-9621/(460+Ta))/100. For instance, the humidity ratio w = 0.0071 pounds of water per pound of dry air on an average 88.9 F July day in Dagget, CA (a very hot and dry climate), so Pa = 29.921/(0.62198/w) = 0.3376 'Hg.
Bowen's 1926 equation says the heat gain from warmer air equals the heat loss by evaporation at the wet bulb temp, independent of wind speed. If we add heat gain from sun (2540 Btu/ft^2/day or 105.8 Btu/h-ft^2 in Dagget), (460+88.9)-Tw + 105.8 = 100(Pw-0.3376), ie 688.5 - Tw = 100Pw, with Tw in Rankine degrees.
Pw = e^(17.963-9621/Tw), so ln(100Pw) = 4.605+17.863-9621/Tw = ln(688.5-Tw), ie Tw = 9621/(22.47-ln(688.5-Tw). Plugging in Tw = 460+88.9 = 548.9 R on the right makes Tw = 548.8 on the left, then 548.82, so the pool and air temps would be about the same.
Pw = e^(17.863-9621/Tw) = 0.717 "Hg, so the pool would evaporate
0.46(0.717-0.3376) = 0.174 inches per day, ie 1" every 5.7 days.Sounds like a leak to me.
Whereabouts, more specifically?
What's the pool temp and air temp and RH?
Is it in sun or shade?
Nick
Used to live in Tucson. Had the same problem. Refilling the pool with hard city water always screwed up the chemistry.
Charlie
Here in the desert southwest, evaporation from open bodies of water is about
7.5 feet per year, probably more than a foot in a typical hot summer month. Days with high temperatures and wind experience the greatest loss. The 1/2" to 1" inch you cite, if it occurs in the summer, seems to be well within the range you might expect. On the other hand, such losses in January might suggest leakage.SJF
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