Disagree. Teaching people to plug high amperage appliances into the SAME outlet is just wrong. They'll tend to generalize and think EVERY outlet can handle 30 or 40A loads. What does your average Joe Homeowner know about Edison circuits? Nada, zip, bupkiss.
Because it's SO simple to add an extra box and circuit when you're doing the work, it seems like very false economy to save a little money (maybe - you've read my comments on wire costs and sales) and create an outlet that encourages people to overload *all* outlets because "the one in the kitchen never blows a breaker." Joe Homeowner is hardly likely to know that just those outlets in the kitchen can handle multiple high-amp loads plugged into them.
If running large loads out of one duplex outlet is the main reason for using Edison circuits (and it's a weak one IMHO) I counter by saying you can do exactly the same thing with a discrete feed from two breakers at the panel with no shared neutral. Same effect.
Then you can pull 40A from one duplex outlet if that's what floats your boat. Doing it with two discrete circuits and no shared neutral means you can use single pole (and MUCH cheaper) GFCIs using the downstream options or GFCI breakers in the circuit panel.
I'm still not convinced Edison circuits are saving anyone any money or makes them safer in any way. Mostly what I've heard is "gee, you can run one less conductor" as if that's really a substantial savings in wiring or labor costs. It's not if you're going to run a new cable anyway.
Explain to me again how you can GFCI protect an Edison circuit with two one pole GFCIs? The current in a shared neutral fluctuates with the load on both phases. Only a dual pole GFCI can monitor both hots simultaneously as I understand it. From what I've read at least some people who have tried to install two single pole GFCIs on an Edison circuit have been plagued by nuisance trips. Others have had success, apparently, by separating the shared neutral into two discrete wires before connection to the GFCIs. But that's no longer a true Edison circuit.
There may be a proper way to do it, but it seems inordinately "klugy" to try to force two single pole GFCIs to do something they weren't designed to do. It seems a long way to go for very little reward. Just run two circuits instead of an Edison circuit and you can use the much cheaper single pole GFCIs and you can use them in the pass-through mode to protect all downstream outlets.
I'm not the only one who isn't sanguine about MWCs:
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--------------------- Destruction of Equipment. Never remove the grounded (neutral) conductor from the grounded terminal bar in the panelboard if the phase conductors are energized. The grounded (neutral) conductor you remove could be part of a multiwire branch circuit, so this could result in destruction of electrical equipment. More important, even if the return conductor is not part of a multiwire circuit, removing a conductor from the grounded terminal bar when the circuit is energized could result in injury due to shock or arcing.
A typical 3-wire circuit is actually two otherwise-separate parallel circuits with a common conductor. If the grounded (neutral) conductor is accidentally opened, the circuit changes from two separate parallel 120 V circuits to one 240 V series circuit. This can result in fires and the total destruction of electrical equipment.
For example: A single-phase, 3-wire, 120/240 V circuit supplies a 1,275 W,
120 V hair dryer and a 600 W, 120V television. If the grounded (neutral) conductor is interrupted, it will cause the 120 V television to operate at 163 V and consume 1,110 W of power (instead of 600 W) for only a few seconds before it burns up. FigureStep 1. Determine the resistance of each appliance, R = E2/P.
a.. Hair dryer rated 1275 watts at 120 volts. b.. R = E2/P, R = 1202/1275 = 11.3 ohms c.. Television rated 600 watts at 120 volts. d.. R = E2/P, R = 1202/600 = 24 ohms Step 2. Determine the circuit resistance: RT = R1 + R2
a.. RT = 11.3 ohms + 24 ohms = RT = 35.3 ohms Step 3. Determine the current of the circuit: IT = ES/RT
a.. IT = 240 V/35.3 ohms = 6.8 A Step 4. Determine the voltage for each appliance: E = IT x Rx
a.. Hair dryer: 6.8 A x 11.3 ohms = 76.84 volts b.. Television: 6.8 A x 24 ohms = 163.2 volts The 120 V rated TV in the split second before it burns up or explodes is operating at 163.2 volts.
Step 5. Determine the power consumed by each appliance: P = E2/R
a.. Hair Dryer: P = 76.82/11.3 = 522 watts b.. Television: P = 163.22/24 = 1100 watts The 600 W, 120 V rated TV will operate at 163 volts and consume 1110 watts. You can kiss this TV goodbye!
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All to save (perhaps) a few bucks on cable costs. Not worth it.