Ya, I am to. But first let me say this, The first spec you posted,
0* 14' plus or minus 10', seems this isn't as critical as some posters are making it. For toe, it is still a trig problem, but the problem is defining, side b (a reference point).I wonder do the shops attach a laser and measure on a wall scale a defined distance away?
I don't know this, is it a single adjustment that moves both wheels or do you adjust both wheels separately? (makes a reference even more important) Sorry just thinking on the keypad.
You have a trig problem and a measurement problem. The measurement problem is more difficult.
It is not be hard to convert the 14 minutes to inches using the wheel diameter as one line. The angle is how much more is the front of the wheel turned in more than the rear of the wheel. I'll call the wheel 16" from front to rear. (just realized this almost the same trig problem for camber, just rotated 90*)
I'm using the trig calculator above, this time the orientation is correct. Put the following numbers in, (side c) = 16, (angle A) = .233. The angle is .233 because 14min/60min = .233. Your answer is (side a) which is 0.065". So, you want the rear of a 16" wheel stick out 0.065" more than the front. Not real easy to measure, But, if you could extend the 16" to 12 ft (192") with a laser pointer, then (side a) is 0.781". The laser must be perfectly square with the wheel. Just some thinking. Hope it makes some sense. Mikek